Feet size to height ratio

[azekeil]

This morning's conversation has resulted in a study. Please divide your height by the size of your feet (measured in inches or cm or something - not your shoe size) and select your result on this poll:

[Poll #163963]

Update: The resulting ratio tells you how many of your feet you are tall. It's just a piece of silliness but it made me curious. It also gives you an idea of how physically stable or not you should be. So it's a stupid measure. So what? It's just a bit of fun. I just wanted to know if there's a difference between males and females.. I know, I should have posted two polls but I did it this morning when I wasn't awake. Bleh.

Comments

Ummmm...

[lazrus-armagedn.livejournal.com]

Mine turned out to be 42.8 ( = 43 ), but you don't have a lower value than 60!



What's this all about, anyway?

[azekeil.livejournal.com]

Are you sure?? That means you are only just over 4 of your feet tall!

[lazrus-armagedn.livejournal.com]

OK...

(My height (1.80m = 180cm) / my EU shoe size (42cm)) * 10

= (180/42)*10

= 4.28 * 10

= 42.8


Or am I missing something?

[azekeil.livejournal.com]

Dude, I said NOT your shoe size. If your feet are seriously close to half a meter long you should talk to the Guinness Book of Records! Take out a ruler/tape measure and use that.

[caz.livejournal.com]

Hope you dont mind me adding you. I am on Kissycats list, and I always find myself coming to your journal from hers to read stuff :)

[azekeil.livejournal.com]

You're welcome, but you'll forgive me if I don't add you back. I simply don't have time to read everything you post!

[caz.livejournal.com]

I dont post that much anymore lol

I'm not entirely sure...

[lazrus-armagedn.livejournal.com]

...how excited I am by the results of this poll

[gerald_duck]

Are you intending a follow-up survey, to test a more traditional correlation between foot size and a certain other biometric?

[azekeil.livejournal.com]

No, it was a stand-alone survey (*chortle*)

[chocojon.livejournal.com]

You could try circumference of head vs. height (both in cm) as a percentage.
I think I know the answer to this and it proves to be a constant in all but two of the people that I've asked.